-(0.006x^2-0.18x+0.0195)=0

Solution for -(0.006x^2-0.18x+0.0195)=0 equation:

-(0.006x^2-0.18x+0.0195)=0

We get rid of parentheses

-0.006x^2+0.18x-0.0195=0

a = -0.006; b = 0.18; c = -0.0195;
Δ = b2-4ac
Δ = 0.182-4·(-0.006)·(-0.0195)
Δ = 0.031932
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.18)-\sqrt{0.031932}}{2*-0.006}=\frac{-0.18-\sqrt{0.031932}}{-0.012}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.18)+\sqrt{0.031932}}{2*-0.006}=\frac{-0.18+\sqrt{0.031932}}{-0.012}
$